CS代写 Operating Systems – CSCI 402 – cscodehelp代写 – INTERVIEW&CODEHELP

Operating Systems – CSCI 402
5.1 Threads Implementations
Strategies
A Simple Thread Implementation Multiple Processors
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INT INT
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mutex Memory
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void idle_thread() {
while(1) {
enqueue(runqueue, CurrentThread)
thread_switch()
}
}
yield()
Operating Systems – CSCI 402
Straight-threads – Multiple Processors
thread_switch() is no longer sufficient
it¡¯s meant for uniprocessor
Simple approach
run on each processor an idle thread
void thread_switch( ) {
thread_t NextThread, OldCurrent;
NextThread = dequeue(RunQueue);
OldCurrent = CurrentThread;
CurrentThread = NextThread;
swapcontext(&OldCurrent->context,
}
&NextThread->context);
this thread never blocks, so there is always something to run to avoid boundary condition (although this is busy-waiting) code is incomplete (because thread_switch() is incomplete, the way it was presented here )
normal threads join the RunQueue when ready
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if (!m->locked) {
m->locked = 1;
}
if both threads execute the above code concurrently, in different processors, both threads think they got the lock
Operating Systems – CSCI 402
Straight-threads – Multiple Processors
When there are multiple processors, the difficulty lies in locking
m
Memory
No way to implement this with only software
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Hardware Support
Compare and swap machine instruction (pseudo-code in C below)
int CAS(int *ptr, int old, int new) {
int tmp = *ptr; // get the value of mutex
if (tmp == old) // if it equals to old
*ptr = new; // set it to new
return tmp; // return old
}
often implemented as a machine-level instruction
must execute atomically
how do you guarantee that when there are multiple CPUs?
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int CAS(int *ptr, int old, int new) {
int tmp = *ptr; // get the value of mutex
if (tmp == old) // if it equals to old
*ptr = new; // set it to new
return tmp; // return old
}
e.g., assume mutex is unlocked, call CAS(&lock, 0, 1) mutex is represented as a bit, 0 if unlocked, 1 if locked
Operating Systems – CSCI 402
Hardware Support
Compare and swap machine instruction (pseudo-code in C below)
A[0..31]
D[0..31] RD WR
LOCK
&lock 0
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Copyright ý . Systems – CSCI 402
Hardware Support
Compare and swap machine instruction (pseudo-code in C below)
int CAS(int *ptr, int old, int new) {
int tmp = *ptr; // get the value of mutex
if (tmp == old) // if it equals to old
*ptr = new; // set it to new
return tmp; // return old
}
e.g., assume mutex is unlocked, call CAS(&lock, 0, 1) mutex is represented as a bit, 0 if unlocked, 1 if locked
A[0..31]
D[0..31] RD WR
LOCK
&lock &lock 01
Copyright ý . Cheng
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Hardware Support
Compare and swap machine instruction (pseudo-code in C below)
int CAS(int *ptr, int old, int new) {
int tmp = *ptr; // get the value of mutex
if (tmp == old) // if it equals to old
*ptr = new; // set it to new
return tmp; // return old
}
e.g., assume mutex is unlocked, call CAS(&lock, 0, 1) mutex is represented as a bit, 0 if unlocked, 1 if locked
Operating Systems – CSCI 402
A[0..31]
D[0..31] RD WR
LOCK
&lock &lock 01
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int CAS(int *ptr, int old, int new) {
int tmp = *ptr; // get the value of mutex
if (tmp == old) // if it equals to old
*ptr = new; // set it to new
return tmp; // return old
}
Can implement spin lock using CAS()
mutex is represented as a bit, 0 if unlocked, 1 if locked
Naive spin lock
void spin_lock(int *mutex) {
while(CAS(mutex, 0, 1)) // textbook is wrong
; }
void spin_unlock(int *mutex) {
*mutex = 0;
}
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Operating Systems – CSCI 402
Hardware Support
Compare and swap machine instruction (pseudo-code in C below)
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void spin_lock(int *mutex) {
while(CAS(mutex, 0, 1)) // textbook is wrong
; }
void spin_unlock(int *mutex) {
*mutex = 0; }
Better spin lock
void spin_lock(int *mutex) {
while (1) {
if (*mutex == 0) {
// the mutex was at least momentarily unlocked
if (!CAS(mutex, 0, 1))
break; // we have locked the mutex
// some other thread beat us to it, try again
} }
}
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Naive spin lock
Spin Lock
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Copyright ý . Systems – CSCI 402
Blocking Locks
Spin locks are wasteful
processor time wasted waiting for the lock to be released barely acceptable if locks are held only briefly
A better approach is to have a blocking lock
threads wait by having their execution suspended
a thread much yield the processor and join a queue of waiting threads
later on, get resumed explicitly
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Blocking Locks
void blocking_lock(mutex_t *m) {
if (m->holder != 0) {
enqueue(m->wait_queue, CurrentThread);
thread_switch();
} else
m->holder = CurrentThread;
}
void blocking_unlock(mutex_t *m) {
if (queue_empty(m->wait_queue))
m->holder = 0;
else {
m->holder = dequeue(m->wait_queue);
enqueue(RunQueue, m->holder);
}
}
This code only works on a uniprocessor
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threads 1 and 2 can both think they¡¯ve got the lock
Operating Systems – CSCI 402
1,2
void blocking_lock(mutex_t *m) {
if (m->holder != 0) {
enqueue(m->wait_queue, CurrentThread);
thread_switch();
} else
m->holder = CurrentThread;
}
void blocking_unlock(mutex_t *m) {
if (queue_empty(m->wait_queue))
m->holder = 0;
else {
m->holder = dequeue(m->wait_queue);
enqueue(RunQueue, m->holder);
}
}
On a multiprocessor, it may not work (since it has a race condition)
Blocking Lock Failure Scenario (1)
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2
thread 2 holds the mutex and wait queue is empty and thread 1 tries to lock the mutex at the same time thread 2 is releasing the mutex
thread 1 may wait forever
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Operating Systems – CSCI 402
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void blocking_lock(mutex_t *m) {
if (m->holder != 0) {
enqueue(m->wait_queue, CurrentThread);
thread_switch();
} else
m->holder = CurrentThread;
}
void blocking_unlock(mutex_t *m) {
if (queue_empty(m->wait_queue))
m->holder = 0;
else {
m->holder = dequeue(m->wait_queue);
enqueue(RunQueue, m->holder);
}
}
On a multiprocessor, it may not work (since it has a race condition)
Blocking Lock Failure Scenario (2)
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1
void blocking_lock(mutex_t *m) {
if (m->holder != 0) {
enqueue(m->wait_queue, CurrentThread);
thread_switch();
} else
m->holder = CurrentThread;
}
void blocking_unlock(mutex_t *m) {
if (queue_empty(m->wait_queue))
m->holder = 0;
else {
m->holder = dequeue(m->wait_queue);
enqueue(RunQueue, m->holder);
}
}
Maybe we can fix both scenarios by making these two functions mutually exclusive (with respect to mutex m)
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Blocking Lock Failure Scenario (2)
maybe we can using a spin lock!
Operating Systems – CSCI 402
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Working Blocking Locks (?)
void blocking_lock(mutex_t *m) {
spin_lock(m->spinlock); // okay to spin here
if (m->holder != 0) {
enqueue(m->wait_queue, CurrentThread);
thread_switch();
} else {
} m->holder = CurrentThread;
spin_unlock(m->spinlock);
}
void blocking_unlock(mutex_t *m) {
spin_lock(m->spinlock); // okay to spin here
if (queue_empty(m->wait_queue)) {
m->holder = 0;
} else {
m->holder = dequeue(m->wait_queue);
} enqueue(RunQueue, m->holder);
spin_unlock(m->spinlock);
}
Will deadlock because of thread_switch() Copyright ý . Cheng
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Operating Systems – CSCI 402
Working Blocking Locks (?)
void blocking_lock(mutex_t *m) {
spin_lock(m->spinlock);
if (m->holder != 0) {
enqueue(m->wait_queue, CurrentThread);
spin_unlock(m->spinlock);
thread_switch();
} else {
m->holder = CurrentThread;
spin_unlock(m->spinlock);
}
}
void blocking_unlock(mutex_t *m) {
spin_lock(m->spinlock);
if (queue_empty(m->wait_queue)) {
m->holder = 0;
} else {
m->holder = dequeue(m->wait_queue);
} enqueue(RunQueue, m->holder);
spin_unlock(m->spinlock);
}
Has a different problem (race condition!) Copyright ý . Cheng
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spin_unlock(m->spinlock);
}
Thread 1 may be running in both processors!
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Operating Systems – CSCI 402
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Working Blocking Locks (?)
void blocking_lock(mutex_t *m) {
spin_lock(m->spinlock);
if (m->holder != 0) {
enqueue(m->wait_queue, CurrentThread);
spin_unlock(m->spinlock);
thread_switch();
} else {
m->holder = CurrentThread;
spin_unlock(m->spinlock);
}
}
void blocking_unlock(mutex_t *m) {
spin_lock(m->spinlock);
if (queue_empty(m->wait_queue)) {
2
m->holder = 0;
} else {
m->holder = dequeue(m->wait_queue);
} enqueue(RunQueue, m->holder);
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Copyright ý . Blocking Locks (?)
void blocking_lock(mutex_t *m) {
spin_lock(m->spinlock);
if (m->holder != 0) {
enqueue(m->wait_queue, CurrentThread);
spin_unlock(m->spinlock);
thread_switch();
} else {
m->holder = CurrentThread;
spin_unlock(m->spinlock);
}
}
void blocking_unlock(mutex_t *m) {
spin_lock(m->spinlock);
if (queue_empty(m->wait_queue)) {
m->holder = 0;
else {
m->holder = dequeue(m->wait_queue);
} enqueue(RunQueue, m->holder);
spin_unlock(m->spinlock);
}
Can you do spin_unlock() inside thread_switch()? Copyright ý . Cheng
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Operating Systems – CSCI 402

Two system calls are provided to support futexes
futex_wait(futex_t *futex, int val) {
if (futex->val == val)
// sleep on the futex queue inside kernel
}
futex_wake(futex_t *futex) {
// wake up one thread from wait queue if
// there is any
…
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Operating Systems – CSCI 402
: Linux¡¯s fast user-space mutex (for 1 ¡Á 1 model) safe, efficient kernel conditional queueing in Linux
most of the time when you try to lock a mutex, it¡¯s unlocked; so just go ahead and lock it (no system call) if it¡¯s locked (by another thread), then a system call is required for this thread to obtain the lock
contained in it is an unsigned integer state called value and a queue of waiting threads
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Ancillary Functions
Add 1 to *val, return its original value
unsigned int atomic_inc(unsigned int *val) {
// performed atomically
return((*val)++); // textbook is wrong
}
e.g., x86 has “lock-prefixed instructions” so you can lock any consecutive machine instructions together and make them atomic
Subtract 1 to *val, return its original value
unsigned int atomic_dec(unsigned int *val) {
// performed atomically
return((*val)–); // textbook is wrong
}
Just like CAS(), both functions return the previous lock value
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futex->val
0 means unlocked; otherwise, locked
void lock(futex_t *futex) {
unsigned int c;
while ((c = atomic_inc(&futex->val)) != 0)
futex_wait(futex, c+1);
}
void unlock(futex_t *futex) {
futex->val = 0;
futex_wake(futex);
}
Problem with unlock()
slow because futex_wake() is a system call
Problem with lock()
threads run in lock steps in a multiprocessor environment! futex->val may wrap-around
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Operating Systems – CSCI 402
Attempt 1
Copyright ý . Systems – CSCI 402
Attempt 2
futex->val can only take on values of 0, 1, and 2
0 means unlocked
1 means locked but no waiting thread
2 means locked with the possibility of waiting threads
void lock(futex_t *futex) {
unsigned int c;
if ((c = CAS(&futex->val, 0, 1) != 0)
do {
if (c == 2 || (CAS(&futex->val, 1, 2) != 0))
futex_wait(futex, 2);
} while ((c = CAS(&futex->val, 0, 2)) != 0));
}
void unlock(futex_t *futex) {
if (atomic_dec(&futex->val) != 1) {
futex->val = 0;
futex_wake(futex);
}
}
textbook is wrong
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Attempt 2
void lock(futex_t *futex) {
unsigned int c;
if ((c = CAS(&futex->val, 0, 1) != 0)
do {
if (c == 2 || (CAS(&futex->val, 1, 2) != 0))
futex_wait(futex, 2);
} while ((c = CAS(&futex->val, 0, 2)) != 0));
}
void unlock(futex_t *futex) {
if (atomic_dec(&futex->val) != 1) {
futex->val = 0;
futex_wake(futex);
}
}
textbook is wrong
the implementation of futex_wait() and futex_wake() must be atomic to avoid race conditions
Operating Systems – CSCI 402
https://www.akkadia.org/drepper/futex.pdf
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Thread Synchronization Summary
Spin locks
used if the duration of waiting is expected to be small
as in the case at the beginning of blocking_lock() Sleep (or blocking) locks
used if the duration of waiting is expected to be long
Futexes
optimized version of blocking locks
In your kernel assignmen #1, you need to implement kernel threads very different from user threads
keep in mind that the weenix kernel is non-preemptive
the kernel is very powerful (and therefore, must be bug free, and therefore, your code must be bug free)
in kernel assignmen #3, you need to implement user threads/processes (well, MTP=0, still one thread per process)
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CS代写 Operating Systems – CSCI 402 – cscodehelp代写

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